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Jan 16, 2021 2 mins

ValueError: invalid literal for int() with base 10: ‘C’

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Check if a Python list contains integers, but executing the code results in a "ValueError: invalid literal for int() with base 10: 'C'" error in the terminal.

I want to check weather a Python list is having integer or not. But when try to execute the following code, it gives “ValueError: invalid literal for int() with base 10: ‘C’” error.

ar = ['50', '2', 'C', 'D', '+']

for a in ar:
    if int(a):
        print(a)

Why is This Error?

The error message “ValueError: invalid literal for int() with base 10: ‘C’” in Python indicates that you are trying to convert the string ‘C’ to an integer using the int() function, but the string does not represent a valid integer in base 10.

Here’s a breakdown of the key components of the error message

ValueError: This is a built-in exception in Python that is raised when a function receives an argument of the correct type but with an invalid value.

invalid literal for int(): Specifies that the value being passed to the int() function is not a valid literal that can be converted to an integer.

with base 10: Indicates that the conversion is being attempted in base 10, which is the default base for integer representation.

C’: Specifies the problematic value that is causing the error. In this case, the string ‘C’ is not a valid representation of an integer.

To address this error, consider the following steps

Check Input Data: Examine the data that you are trying to convert to an integer. In this case, the string ‘C’ is not a numeric value that can be converted to an integer.

Ensure Valid Input: Make sure that the input data provided to the int() function is a valid numeric literal that can be converted to an integer in base 10. Valid literals include numbers such as ‘123’, ‘-45’, ‘0’, etc.

Example:

try:
    value = int('C')
except ValueError as e:
    print(f"Error: {e}")

Handle Invalid Cases: If the data can potentially include non-numeric values, implement proper error handling to deal with such cases. You can use a try-except block to catch the ValueError and handle it gracefully.

Example:

try:
    value = int('C')
except ValueError as e:
    print(f"Error: {e}. The input is not a valid integer.")
    # Handle the error condition appropriately.

By ensuring that you are trying to convert valid numeric literals to integers and handling potential errors using try-except blocks, you can address the “ValueError: invalid literal for int() with base 10: ‘C’” in your Python code.


Comments


  • Avatar

    Danielle Carline

    Posted on

    Instead of using int() method, you can use isnumeric() or isdigit() methods like this.

    ar = ['50', '2', 'C', 'D', '+', '0.9']
    
    for a in ar:
        if a.isdecimal():
            print(a)
    

    or

    ar = ['50', '2', 'C', 'D', '+', '0.9']
    
    for a in ar:
        if a.isdigit():
            print(a)
    

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